evaluate cosec13 degree upon sec77 degree minus cot20 degree upon tan70 degree
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Cosec13/ sec77- cot20/tan70
=cosec13/ sec(90-13)- cot 20/tan(90-20)
= cosec13/ cosec 13- cot20/cot20.
=1-1
=0
as we know tha sec(90-A)= cosecA, and tan(90-A)= cotA
Hope it is helpful.
=cosec13/ sec(90-13)- cot 20/tan(90-20)
= cosec13/ cosec 13- cot20/cot20.
=1-1
=0
as we know tha sec(90-A)= cosecA, and tan(90-A)= cotA
Hope it is helpful.
kulu3:
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wlcm
what is the meaning of wlcm
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