Math, asked by an8akSAvifarho, 1 year ago

Evaluate: (cosecA-sinA)(secA-cosA) = sinA*cosA

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Answered by praveen19

2

(cosecA-sinA)(secA-cosA)
(1/sinA-sinA)1/cosA-cosA)
(1-sin^2A)/sinA (1-cos^2A)/cosA
cos^2A/sinA * sin^2A/cosA
sinA*cosA

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