Question

Evaluate cot⁻¹ (-√3)

Answer 1

Answer:

Principal value of cot⁻¹ (-√3) is 5π/6

Step-by-step explanation:

we know that the range of principal value of $cot^{-1}x$ is (0,π).

Let cot⁻¹ (-√3) =θ.Then

cot θ = -√3

$- cot(\frac{\pi}{6}) = cot (\pi-\frac{\pi}{6} ) \\\\\\=cot (\frac{5\pi}{6} )$

∴ θ = 5π/6 ∈ (0,π)

Hence,principal value of cot⁻¹ (-√3) is 5π/6.