Math, asked by methegreat, 9 months ago

Evaluate:Cot75°×Cot30°×Cot15°×Tan77°×Tan13°

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Answers

Answered by aryanjain99999
3

Answer:

 \cot(75) \times    \cot(30)   \times \cot(15)   \times \tan(77) \times   \tan(13)  \\  =  \cot(75)  \times  \cot(30)  \times  \ \tan(90 - 15)  \times   \tan(77)  \times  \cot(90 - 13)  \\  =  \cot(75)  \times  \cot(30)  \times  \tan(75)  \times  \tan(77)  \times  \cot(77)  \\  = 1 \times 1 \times  \cot(30)  \\  =  \cot(30 )  =  \sqrt{3}

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Answered by pankajroy2
4

here is ur ansss

cot⁡(75)×cot⁡(30)×cot⁡(15)×tan⁡(77)×tan⁡(13)=cot⁡(75)×cot⁡(30)× tan⁡(90−15)×tan⁡(77)×cot⁡(90−13)=cot⁡(75)×cot⁡(30)×tan⁡(75)×tan⁡(77)×cot⁡(77)=1×1×cot⁡(30)=cot⁡(30)=3\begin{lgathered}\cot(75) \times \cot(30) \times \cot(15) \times \tan(77) \times \tan(13) \\ = \cot(75) \times \cot(30) \times \ \tan(90 - 15) \times \tan(77) \times \cot(90 - 13) \\ = \cot(75) \times \cot(30) \times \tan(75) \times \tan(77) \times \cot(77) \\ = 1 \times 1 \times \cot(30) \\ = \cot(30 ) = \sqrt{3}\end{lgathered}

cot(75)×cot(30)×cot(15)×tan(77)×tan(13)

=cot(75)×cot(30)× tan(90−15)×tan(77)×cot(90−13)

=cot(75)×cot(30)×tan(75)×tan(77)×cot(77)

=1×1×cot(30)

=cot(30)=

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