Math, asked by nitesh2257, 1 year ago

Evaluate cube root of 1512 divided by cube root of 2401


nitesh2257: Answer please

Answers

Answered by MaheswariS
22

Answer:

\frac{\sqrt[3]{1512}}{\sqrt[3]{2401}}=\frac{6}{7}

Step-by-step explanation:

\sqrt[3]{1512}

=\sqrt[3]{3*504}

=\sqrt[3]{3*3*168}

=\sqrt[3]{3*3*3*56}

=\sqrt[3]{3^3*7*2^3}

\sqrt[3]{2401}

=\sqrt[3]{7*343}

=\sqrt[3]{7*7^3}

Now,

\frac{\sqrt[3]{1512}}{\sqrt[3]{2401}}

=\sqrt[3]{\frac{1512}{2401}}

=\sqrt[3]{\frac{3^3*7*2^3}{7*7^3}}

=\sqrt[3]{\frac{3^3*2^3}{7^3}}

=\frac{3*2}{7}

=\frac{6}{7}

\frac{\sqrt[3]{1512}}{\sqrt[3]{2401}}=\frac{6}{7}


KAKULSHARMA: thanks
MaheswariS: ok
KAKULSHARMA: hii
Answered by pardeepbatish3
4

Step-by-step explanation:

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