Math, asked by NEERAj1987, 1 year ago

Evaluate cube root of 7 multiplied by the square root of 7 over sixth root of 7 to the power of 5 .

Answers

Answered by Robin0071
0
Solution:-

given by:-

 \frac{ \sqrt[3]{7}  \times  \sqrt[2]{7} }{ { (\sqrt[6]{7}) }^{5} }  \\  \frac{ {7}^{ \frac{1}{3}  +  \frac{1}{2} } }{ {7}^{ \frac{1}{6} \times 5 } }  \\   \frac{ {7}^{ \frac{5}{6} } }{ {7}^{ \frac{5}{6} } }  \\  {7}^{ \frac{5}{6} -  \frac{5}{6}  }  \\  {7}^{0}  \\ 1 \: ans
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