Question

Evaluate \dfrac c2-3+\dfrac 6d
2
c
​
−3+
d
6
​
start fraction, c, divided by, 2, end fraction, minus, 3, plus, start fraction, 6, divided by, d, end fraction when c=14c=14c, equals, 14 and d=3d=3d, equals, 3.

Answer 1

Evaluation is $\frac{c}{2}-3+\frac{6}{d}=6$

Step-by-step explanation:

Given : Expression $\frac{c}{2}-3+\frac{6}{d}$

when c=14 and d=3.

To find : Evaluate the expression ?

Solution :

Expression $\frac{c}{2}-3+\frac{6}{d}$

Substitute c=14 and d=3,

$\frac{c}{2}-3+\frac{6}{d}=\frac{14}{2}-3+\frac{6}{3}$

$\frac{c}{2}-3+\frac{6}{d}=7-3+2$

$\frac{c}{2}-3+\frac{6}{d}=6$

Therefore, evaluation is $\frac{c}{2}-3+\frac{6}{d}=6$

#Learn more

Evaluate \dfrac c2-3+\dfrac 6d 2 c ​ −3+ d 6 ​ when c=14c=14 and d=3d=3.

https://brainly.in/question/8168292

Answer 2

Answer:

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