Math, asked by Kiara11151, 10 months ago

.......................... Evaluate ............................
.
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Answered by mysticd
3

 \red { Value \: of \: \Big(\frac{sin 27\degree}{cos 63\degree}\Big)^{2} + \Big(\frac{cos 63\degree}{sin 27\degree}\Big)^{2}}

 = \Big(\frac{sin 27\degree}{cos (90 - 27\degree)}\Big)^{2} + \Big(\frac{cos 63\degree}{sin (90 - 63\degree}\Big)^{2}

 = \Big(\frac{sin 27\degree}{sin 27\degree}\Big)^{2} + \Big(\frac{cos 63\degree}{cos 63\degree}\Big)^{2}

 = 1 + 1 \\= 2

Therefore.,

 \red { Value \: of \: \Big(\frac{sin 27\degree}{cos 63\degree}\Big)^{2} + \Big(\frac{cos 63\degree}{sin 27\degree}\Big)^{2}} \green {= 1 }

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Answered by sumitkaushik291
0
here is your answer dear
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