Question

Evaluate : ∫dx/1+x^2 for x→[1,√3]

Answer 1

$\textbf{Hello Mate...}$☺☺

$\textbf{Question}$>>>∫dx/1+x^2 for x→[1,√3]

$\textbf{Your Answer....}$

= [${tan}^-1$x] >>for x = [ 1 , √3]

= ${tan}^-1$(√3) - ${tan}^-1$(1)

= $\frac{π}{3}$ - $\frac{π}{4}$

= $\frac{4π - 3π}{12}$

= $\frac{π}{12}$

Be... Brainlyy..

@karangrover12