Question

evaluate dy/dx when , y= sinx/cosx​

Answer 1

Answer:

y=sinx/cosx

diff. b/s w.r.t x

dy/dx=cosx/-sinx

Answer 2

Answer:

Step-by-step explanation:

y= sinx/cosx

dy/dx​= { cosx*d/dx(sinx)-sinx*d/dx( cosx )}/(cosx)²

={cosx*cosx-sinx(-sinx) } /cos²x

=( cos²x+sin²x)/cos²x

=1/cos²x

=sex²x