evaluate dy/dx when , y= sinx/cosx
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Answered by
0
Answer:
y=sinx/cosx
diff. b/s w.r.t x
dy/dx=cosx/-sinx
Answered by
1
Answer:
Step-by-step explanation:
y= sinx/cosx
dy/dx= { cosx*d/dx(sinx)-sinx*d/dx( cosx )}/(cosx)²
={cosx*cosx-sinx(-sinx) } /cos²x
=( cos²x+sin²x)/cos²x
=1/cos²x
=sex²x
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