Evaluate ✓dz/z-7z+12 where c is the circle [z]=3.5
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c=4.5 cm
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Cauchy's Integral theorem ∫Cf(z)z−zodz=2πif(zo) .Clearly the singularity z=7+4√12 lies outside the contour and the singularity 7−4√12 lies inside it so f(z)=(z3+z+1)z−7+4√12 .Using Cauchy's Residue theorem we get the contour integral as 2πif(7−4–√12)
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