Math, asked by adarshjhariya286, 11 months ago

Evaluate: ∫e2logx−1e2logx+1dx

Answers

Answered by portia85
0

Answer:

X+c

Step-by-step explanation:

 \int \:( e  \times log( {x}^{2}) - e \times  log( {x}^{2}  )  + 1 )dx\\  \int \: dx \\ x + c

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