Math, asked by khairagagandeep19, 1 month ago

evaluate each of the following(e) 13 = [(-2) + 1]​

Answers

Answered by FBIopendoornow
0

Answer:

(a) -30\ \times\frac{1}{10}−30 ×  

10

1

​  

 

= -3

(b) 50\times\frac{-1}{5}50×  

5

−1

​  

 

= -10

(c) -36\ \times\frac{-1}{9}−36 ×  

9

−1

​  

 

= 4

(d) \left(-49\right)\times\frac{1}{49}(−49)×  

49

1

​  

 

= -1

(e) 13\times\left[\left(-2\right)\ +\ 1\right]13×[(−2) + 1]

13\times\frac{-1}{1}13×  

1

−1

​  

 

= -13

(f) 0\times\frac{-1}{12}0×  

12

−1

​  

 

= 0

(g) \left(-31\right)\div\left[\left(-30\right)-1\right](−31)÷[(−30)−1]

\left(-31\right)\div\left(-31\right)(−31)÷(−31)

-31\ \times\frac{-1}{31}−31 ×  

31

−1

​  

 

= 1

(h)\left[\left(-36\right)\div12\right]\div3[(−36)÷12]÷3

\left[\left(-36\right)\times\frac{1}{12}\right]\times\frac{1}{3}[(−36)×  

12

1

​  

]×  

3

1

​  

 

\frac{-36}{12}\times\frac{1}{3}  

12

−36

​  

×  

3

1

​  

 

-3\times\frac{1}{3}−3×  

3

1

​  

 

= 1

(i) \left[-6+5\right]\div\left[-2+1\right][−6+5]÷[−2+1]

-1\times\frac{-1}{1}−1×  

1

−1

​  

 

= 1

Step-by-step explanation:

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