Question

Evaluate each of the following:
i) sin30° + cos 45º + tan 180°​

Answer 1

Answer:√2+2/2√2

Step-by-step explanation:

=Sin30°+Cos45°+tan180°

=1/2+1/√2+0

=√2+2/2√2

Value of tan 180°=0(by ASTC rule)

i.e; tan180°=tan(270°-90°)

= -cot90°

=0

Answer 2

Answer:

$\sin30^\circ+ \cos 45\circ+ \tan 180^\circ=\frac{\sqrt2+2}{2\sqrt2}$          

Step-by-step explanation:

Given : Expression $\sin30^\circ+ \cos 45\circ+ \tan 180^\circ$

To find : Evaluate the expression ?

Solution :

We know the values of trigonometric terms like,

$\sin30^\circ=\frac{1}{2}$

$\cos 45\circ=\frac{1}{\sqrt2}$

$\tan 180^\circ=0$

Substitute the values in the expression,

$\sin30^\circ+ \cos 45\circ+ \tan 180^\circ$

$=\frac{1}{2}+\frac{1}{\sqrt2}+0$

$=\frac{\sqrt2+2}{2\sqrt2}$

Therefore, $\sin30^\circ+ \cos 45\circ+ \tan 180^\circ=\frac{\sqrt2+2}{2\sqrt2}$