Evaluate each of the following in terms of x and y, if it is given x=log, 3 and
y=log 5 base2
(i) log15base2
(ii) log 7.5base2 (iii) log60base2 (iv) log6750bsae2
please answer fast
Answers
Step-by-step explanation:
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Answer:
(i) log₂15 = x + y
(ii) log₂(7.5) = x + y - 1
(iii) log₂60 = x + y + 2
(iv) log₂(6750) = 3x + 3y + 1
Step-by-step explanation:
Given: x = log₂3 and y = log₂5
(i) Given: log₂15
= log₂(3×5)
= log₂3 + log₂5
= x + y
So, log₂15 = x + y
(ii) Given: log₂(7.5)
= log₂ (15/2)
= log₂ 15 - log2
= log₂(3×5) - 1
= log₂3 + log₂5 - 1
= x + y - 1
So, log₂(7.5) = x + y - 1
(iii) Given: log₂60
= log₂ (15×4)
= log₂15 + log₂4
= log₂ (3×5) + log₂ (2²)
= log₂3 + log₂5 + 2 log₂2
= x + y + 2
So, log₂60 = x + y + 2
(iv) Given: log₂ 6750
= log₂ (15×45×10)
= log₂ (3×5×3×3×5×2×5)
= log₂ (3³ × 5³ × 2)
= log₂3³ + log₂5³ + log₂2
= 3 log₂3 + 3 log₂5 + 1
= 3x + 3y + 1
So, log₂(6750) = 3x + 3y + 1
Formulas used :-
1) logₐ (mn) = logₐm + logₐn
2) logₐ (m/n) = logₐm - logₐn
3) logₐ (mⁿ) = n logₐm
4) logₐ a = 1