Question

evaluate each of the following in terms of x and y,if it us given x=log2power3 and y=log2power5
1.log2power60
please any one solve this for me​

Answer 1

Answer:

no no nonnonononno no no no no no no no no no no no

Answer 2

Answer:

1. $x=0.903$

2. $y=1.505$

3. $m=18.06$

Solution:

1. x=log2power3

$x=\log 2^{3}$

This follows the logarithms of power.

In this rule, if the n power of a quantity is n times logarithm of the quantity.

$\log _{\mathrm{e}} x^{n}=n \log _{e} x$

On applying the rule,

$\Rightarrow x=3 \log 2$

The value of log⁡2 is 0.301

On substituting the values,

$\Rightarrow x=3(0.301)$

$\therefore x=0.903$

2. y=log2power5

$y=\log 2^{5}$

This follows the logarithms of power.

In this rule, if the n power of a quantity is n times logarithm of the quantity.

$\log _{\mathrm{e}} x^{n}=n \log _{e} x$

On applying the rule,

$\Rightarrow y=5 \log 2$

The value of log⁡2 is 0.301

On substituting the values,

$\Rightarrow y=5(0.301)$

$\therefore y=1.505$

3. log2power60

$\Rightarrow \log 2^{60}$

Let’s assume the given expression as ‘m’.

$\Rightarrow m=\log 2^{60}$

This follows the logarithms of power.

In this rule, if the n power of a quantity is n times logarithm of the quantity.

$\log _{\mathrm{e}} x^{n}=n \log _{e} x$

On applying the rule,

$\Rightarrow m=60 \log 2$

The value of log⁡2 is 0.301

On substituting the values,

$\Rightarrow m=60(0.301)$

$\therefore m=18.06$