Evaluate each of the following polynomials for the indicated value of the variable . 2x³-3x²- 3x +12 for x=-2
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Firstly, you can easily verify that f(2)<0<f(3), and hence there is a solution x between 2 and 3. In order to find it change the variable x to z=x-1/2, or x=z+1/2. The polynomial will turn into g(z)=2*z^3-(9/2)*z-4, After dividing by 2 you would like to solve the equation z^3-(9/4)*z-2=0. That cubic is of the form z^3–3pz-2q=0 with p=3/4 and q=1. Now you may apply the well known Cardano’s formula for the solution of that cubic to get:
z=(q+sqrt(q^2-p^3))^(1/3)+((q-sqrt(q^2-p^3))^(1/3)
to which you add 1/2 to get the answer
x=z+1/2
which is about
x=2.3285894133483921557662390296674
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