Question

Evaluate each of the following $\frac{4}{cot^{2}30^{0} }+\frac{1}{sin^{2}60^{0} }-cos^{2} 45^{0}$

Answer 1

SOLUTION :

Given:

4/cot²30° + 1/sin² 60° - cos² 45°  

=  4/(√3)² + 1/(√3/2)² - (1/√2)²

[cot 30° = √3 , sin 60° = √3/2 ,  cos  45° = 1/√2]

= 4 / 3 + 1/ ¾ - 1/2

= 4 / 3 + 1× 4/3  - 1/2

= (4 / 3 + 4/3)  - 1/2

= (4+4)/3 - 1/2

= 8/3 - 1/2

= (8×2 - 1×3)/6

[By taking L.C.M of 3 & 2. L.C.M is 6]

= (16 - 3)/6  = 13/6

4/cot²30° + 1/sin² 60° - cos² 45° = 13/6

Hence, 4/cot²30° + 1/sin² 60° - cos² 45° = 13/6

HOPE THIS ANSWER WILL HELP YOU…

Answer 2

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here's the answer.......

attached in the pic...

hope it helps you ✔✔✌✌⭐⭐☺☺⭐⭐.

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