Math, asked by ganag9566, 3 months ago

evaluate each of the following using identies (10001)^2​

Answers

Answered by farhaanaarif84
0

Answer:

(1001)

3

=(1000+1)

3

Suitable identities is (x+y)

3

=x

3

+3x

2

y+3xy

2

+y

3

∴(1000+1)

3

=(1000)

3

+3(1000)

2

(1)+3(1000)(1)

2

+(1)

3

=1000000000+3000000+3000+1=1003003001

Answered by Anonymous
2

Your answer is 17...

Hope this'll help you.

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