Question

evaluate evaluate using proper identity 97×98

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Answer 1

Answer:

Formula used

$(x + a)(x + b) = {x}^{2} + (a + b)x + ab$

$97 \times 98 = (100 - 3)(100 - 2) \\ by \: using \: the \: formule \\ ( {100)}^{2} - ( - 3 - 2)100 + ( - 3 \times - 2) \\ = 10000 - 600 + 6 \\ = 9406$

your answer is 9406

Hope it is helpful for you

Answer 2

Answer:

$\huge\sf\pink{Ans}\purple{wer} \:$

$\huge\sf{98 \times 97}$

$\sf\red{(100 - 2)(100 - 3)}$

$\sf\red{ =10 {0}^{2} + ( - 2 - 3)100 + ( - 2)( - 3) }$

$\sf\red{ = 10000 - 5 \times 100 + 6}$

$\sf\red{ = 10006 - 500 } \: \sf\orange{ =9506 }$

using identity :

$\sf\purple{ = (x + a)(x + b) = {x}^{2} + (a + b)x + ab }$

Step-by-step explanation:

i hope it helps you

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