Question

evaluate: explain in..​

Answer 1

= > $\frac{cos35}{sin55} + \frac{sin12}{cos78} - \frac{cos18}{sin72}$

= > $\frac{cos(90 - 55)}{sin55} +\frac{sin (90-78)}{cos78} -\frac{cos(90-72)}{sin72}$

= > $\frac{sin55}{sin55} +\frac{cos78}{cos78} -\frac{sin72}{sin72}$                                    $[cos(90-\alpha ) = sin\alpha ]$

= > $1 + 1 - 1 = 1$

Answer 2

Answer:

shshhshdhdhdhdjdjjdjdjdjd