Math, asked by itzdaud, 8 months ago

Evaluate f(2) - f(1)
f(x) = 6x + 1​

Answers

Answered by Anonymous
1

Answer:

f(x) = 6x + 1 \\  \\ f(2) = 6 \times 2 + 1 = 13 \\  \\ f(1) = 6 \times 1 + 1 = 7 \\  \\ f(2) - f(1) = 13 - 7 = 6

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Answered by shraddhald2003
2

Answer:

Step-by-step explanation:

Answer:  f(x)≈8.255096x−8.981920 .

I'm assuming that the question is not in error. But if it actually means to ask “How do I evaluate  f(2)−f(1)  where  f(x)=6x+1 ?”, then the answer is  13–7=6 . If this is the case then please be very careful how you word your questions.

Check:

f(2)−f(1)f(x)=7.528272+0.726824(8.255096x−8.981920)=6.0000018951x+0.99999697792≈6x+1  

Assume that  f(x)  has the form  f(x)=ax+b .

f(2)−f(1)f(x)⇒=(2a+b)−(a+b)(ax+b)=−(a+b)ax+(2a+b)−(a+b)b=6x+1−(a+b)a(2a+b)−(a+b)b=6=1  

Solving for a and b we get

a3−7a2−6a−36=0b=−a−6a  

Using numerical methods we find the that only real solution is

a≈b≈8.25509646356−8.98192019317  

ALTERNATE ANSWER,

f(x1)=6x1+1; f(x2)=6x2+1

f(x1)-f(x2)=6x1+1–6x2–1=6(x1-x2)

let x1=2, x2=1; f(2)-f(1)=6(2–1)=6

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