Evaluate f(2) - f(1)
f(x) = 6x + 1
Answers
Answer:
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Answer:
Step-by-step explanation:
Answer: f(x)≈8.255096x−8.981920 .
I'm assuming that the question is not in error. But if it actually means to ask “How do I evaluate f(2)−f(1) where f(x)=6x+1 ?”, then the answer is 13–7=6 . If this is the case then please be very careful how you word your questions.
Check:
f(2)−f(1)f(x)=7.528272+0.726824(8.255096x−8.981920)=6.0000018951x+0.99999697792≈6x+1
Assume that f(x) has the form f(x)=ax+b .
f(2)−f(1)f(x)⇒=(2a+b)−(a+b)(ax+b)=−(a+b)ax+(2a+b)−(a+b)b=6x+1−(a+b)a(2a+b)−(a+b)b=6=1
Solving for a and b we get
a3−7a2−6a−36=0b=−a−6a
Using numerical methods we find the that only real solution is
a≈b≈8.25509646356−8.98192019317
ALTERNATE ANSWER,
f(x1)=6x1+1; f(x2)=6x2+1
f(x1)-f(x2)=6x1+1–6x2–1=6(x1-x2)
let x1=2, x2=1; f(2)-f(1)=6(2–1)=6
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