Evaluate ƒ(x) = –x2 + 1 for x = –3.
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heya....
Here is your answer....
f (x) = -x^2+1
x = -3
Substitute the value of x in f (x).
-(-3)^2+1
(3)^2+1
9+1
10
It may help you....☺☺
Here is your answer....
f (x) = -x^2+1
x = -3
Substitute the value of x in f (x).
-(-3)^2+1
(3)^2+1
9+1
10
It may help you....☺☺
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