Math, asked by shawkiarn, 8 months ago

evaluate for x:(root3/root5)to the power x+1=125/27​

Answers

Answered by sk181231
15

Answer:

x =  \sqrt{5}  +  \sqrt{3}

x =  \sqrt{5}  -  \sqrt{3}

( \sqrt{5}  +  \sqrt{3}  \: )

( \sqrt{5}  -  \sqrt{3} )

8 + 2 \sqrt{15}

 5 - 3

 = 4 + 15

4 - 15

16² - 2 = 254

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