Evaluate given trigonometry equation 2sin² 0 (theta)- cos 0(theta)= 1
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sorry i didn't understand
Step-by-step explanation:
sorry
Answered by
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Answer:
Step-by-step explanation:
2sin^2 theta - cos theta = 1
2 sin^2 theta = cos theta + 1
2 [ 1 - cos^2 theta] = 1+ cos theta. ( here sin^2theta =1-cos^2 theta)
2 [ (1+ cos theta) ( 1 - cos theta)] = 1 + cos theta ( we know a^2-b^2=(a+b)(a-b))
2(1 +cos theta ) = 1
2 + 2 cos theta = 1
2cos theta = 1 -2
cos theta = -1/2
so , theta = 120 degree
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