Math, asked by adubey8839966369, 4 months ago

Evaluate given trigonometry equation 2sin² 0 (theta)- cos 0(theta)= 1​

Answers

Answered by athultyavg
0

Answer:

sorry i didn't understand

Step-by-step explanation:

sorry

Answered by cherukellajahnavi
0

Answer:

Step-by-step explanation:

2sin^2 theta - cos theta = 1

2 sin^2 theta = cos theta + 1

2 [ 1 - cos^2 theta] = 1+ cos theta.                   ( here sin^2theta =1-cos^2 theta)

2 [ (1+ cos theta) ( 1 - cos theta)] = 1 + cos theta  ( we know a^2-b^2=(a+b)(a-b))

2(1 +cos theta ) = 1

2 + 2 cos theta = 1

2cos theta = 1 -2

cos theta = -1/2

so , theta = 120 degree

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