Evaluate
{i^100-(1/i) ^151}^3
Answers
Answered by
34
How can we prove that (1+i) ^100+(1-i) ^100 =-2^51?
LHS
(1+I)^100+(1-i)^100
This can be written as
(1+i)^(2*50)+(1-i)^(2*50)
Now i^2=-1 so
Expanding this we get
(1+2i+i^2)^50+(1-2i+i^2)^50
(2i)^50+(-2i)^50
Now we can take out 2^50 common
So
(2^50)(i^50+(-i)^50)
As square of the value is always positive we can write this as
We can write this as
(2^50)(i^(2*25)+(i)^(2*50))
As i^2=-1
So
(2^50)((-1)^25+(-1)^25)=2^50*(-1-1)
=-2^51
LHS=RHS
Similar questions