Math, asked by swarpita36, 11 months ago


Evaluate (i) 101 X 102 using identity​

Answers

Answered by veerendrakumaruppu
9
101 x 102

= (100 + 1)*(100 + 2)

= 100*100 + 100*2 + 1*100 + 1*2

= 10000 + 200 + 100 + 2

= 10302 ——> Answer
Answered by Samsriti
4

Answer:

(100+1)*(100+2)

100*100+100(1+2)+1*2

10000+300+2

10302

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