Math, asked by vishruthh, 1 year ago

evaluate: i^24 + (1/i)^26

Answers

Answered by Sattwik7
37
(i^4)^6 + (-i^4)^6 × (-i)^2
= 1 + 1(-1)
= 1 - 1
= 0
I hope you enjoyed.
Answered by syedkamil434oxvlv7
14
i^{4n} =1 now i^{4(6)} =1
now  i^{4n+2)= -1 i^{4(6)+2}=-1 now i^{24} +1/i ^{26} =1-1=0 
therfore 0 is answer
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