Question

evaluate :- i^29 + 1/i^29​

Answer 1

Answer:0

Step-by-step explanation:

i^29 + 1/i^29

(i^2)^14×i + 1/(i^2)^14×i

As i^2=-1 so by equating this we get

i+1/i

Now by taking LCM we get

(i^2 + 1)/i

(-1 + 1)/I

0/i

=0