Question

evaluate i^40 + i^70 + i^96 + i^108​

Answer 1

hii friend

Answer:

2

Step-by-step explanation:

i⁴⁰+i⁷⁰+i⁹⁶+i¹⁰⁸

=i⁴⁰(1+i³⁰+i⁵⁶+i⁶⁸)

=i⁴⁰(1+(i²)¹⁵+(i²)²⁸+(i²)³⁴)                since i⁴ⁿ=1and i²=-1

=1(1+(-1)+1+1)

=2

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