evaluate: i^592 + i^590 + i^588 + i^586 + i^584 / i^582 + i^580 + i^578 + i^ 576 + i^ 574
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Answered by
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we can write the above question in this form
(i^2)^296 + (i^2)^295 + (i^2)^294 + (i^2)^293 +(i^2)^292 + (i^2)^291 + (i^2)^290 + (i^2)^289 + (i^2)^288 + (i^2)^287=
we know that i^2 is -1
subsitute it in the above information..
now if the power is odd then it(i.e., -1) will remain as -1.... because (-1)^3 is -1×-1×-1= -1 right! ..if the power is even it will become 1.... eg..(-1)^2= -1×-1=1 right!.
but for huge numbers, to check whether the power is even or odd..we can simply divide it with 2..if the number is divisible by 2 then it is even number if not then it is odd number...eg..296 is divisible be by 2 ..2×148 so even number....in the same way for all numbers...we get
1 + (-1) + 1 + (-1) + 1 + (-1) + 1 + (-1) + 1 + (-1) =0 ..is the answer
(i^2)^296 + (i^2)^295 + (i^2)^294 + (i^2)^293 +(i^2)^292 + (i^2)^291 + (i^2)^290 + (i^2)^289 + (i^2)^288 + (i^2)^287=
we know that i^2 is -1
subsitute it in the above information..
now if the power is odd then it(i.e., -1) will remain as -1.... because (-1)^3 is -1×-1×-1= -1 right! ..if the power is even it will become 1.... eg..(-1)^2= -1×-1=1 right!.
but for huge numbers, to check whether the power is even or odd..we can simply divide it with 2..if the number is divisible by 2 then it is even number if not then it is odd number...eg..296 is divisible be by 2 ..2×148 so even number....in the same way for all numbers...we get
1 + (-1) + 1 + (-1) + 1 + (-1) + 1 + (-1) + 1 + (-1) =0 ..is the answer
Sania05:
how i can write the eq in the form which u tell
how i can write the eq in the form which u tell
how i can write the eq in the form which u tell
how i can write the eq in the form which u tell
how we can write the eq in the form which u tell
sorry .. my phone was hang
its ok re.... and yeah we should simply the question inorder to obtain answer.....
*simplify
i got it thank u...
(2^2)^2 means 2^4 know! ..i did it in reserve from 2^4 into (2^2)^2.... and yeah ur most welcome..(thanks for your question too because without your question, i cannot express myself..so should thank u also).have a nice day
Answered by
66
Guys answer is in the pic!
Hope its helpful!!
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