evaluate (-i^80)
minus iota power 80
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Answer:
Ans 1
Step-by-step explanation:
(-i)⁸⁰
= ((-i)²)⁴⁰
=(i²)⁴⁰
=(-1)⁴⁰
=( (-1)²)²⁰
=1²⁰
=1
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