evaluate i^n+i^n+1+i^n+2+i^n+3.
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i^n + i^(n+1) + i^(n+2) + i^(n+3)
=i^n[1+i^1+i^2+i^3]
=i^n[1+i-1-i]
=i^n(0)
=0
=i^n[1+i^1+i^2+i^3]
=i^n[1+i-1-i]
=i^n(0)
=0
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