Question

evaluate i^n+i^n+1+i^n+2+i^n+3.

Answer 1

i^n + i^(n+1) + i^(n+2) + i^(n+3)
=i^n[1+i^1+i^2+i^3]
=i^n[1+i-1-i]
=i^n(0)
=0