Math, asked by Anonymous, 1 year ago

Evaluate : (i) Sin 18°/
Cos 72°​

Answers

Answered by ksonakshi70
5

Answer:

 \frac{ \sin(18) }{ \cos(72) }  =  \frac{ \sin(90 - 72) }{ \cos(72) }  \\  =  \frac{ \cos(72) }{ \cos(72) }  \\  = 1

We know that

 \sin(90 - theta)  =  \cos(theta)

Answered by srinivaschintu
3

Answer:

Sin 18°/cos 72°

We can write sin as Cos 72°

( sin(90-A)=cos A)

(sin (90°-18°) = cos 72°)

( sin 72° = cos 72°)

So, cos 72°/cos 72° = 1

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