Math, asked by krish09888, 1 month ago

Evaluate:
(i) sin²63°+ sin²27°/ cos²17°+ 73°
(ii) sin25° cos65° + cos25°sin65°​

Answers

Answered by Anonymous
3

Answer:(sin^2theta+cos^2theta=1)

sin(90-theta) =cos theta, cos(90-theta) =sin theta

1) sin^2(90-27) +sin^2 27/cos^2(90-73) +cos^73

=cos^2 27+sin^2 27/cos^2 73+sin^2 73

=1/1=1

2) sin(65°+25°) =sin(90°) =1

mark as brainlest answer

Similar questions