Math, asked by harshu3778, 10 months ago

Evaluate :

i) tan 36°/cot 54°
ii) cos 12° - sin 78°
iii) cosec 31° - sec 58°

Answers

Answered by EthicalElite
11

i) tan36°/cot54°

=tan(90°-54°)/cot 54°

=cot54°/cot54°

=1

ii) cos12°- sin78°

=cos(90°-78°) - sin78°

=sin78°- sin78°

=0

iii) cosec 31° - sec 58°

=cosec 31° - sec (90° - 31°)

=cosec 31° - cosec 31°

=0

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Answered by Anonymous
48

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Evaluate :\\

i) tan 36°/cot 54°

ii) cos 12° - sin 78°

iii) cosec 31° - sec 58°

\\

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i) Given that : tan 36°/cot 54°

➟ tan 36°/cot (90° - 36°)

➟ [∵ cot (90 - ⊖) = tan ⊖]

➟ tan 36°/tan 36° = 1

\\

ii) Given that : cos 12° - sin 78°

➟ cos 12° - sin (90° - 12°)

➟ [∵ sin (90 - ⊖) = cos ⊖]

➟ cos 12° - cos 12° = 0

\\

iii) Given that : cosec 31° - sec 59°

➟ cosec 31° - sec (90° - 31°)

➟ [∵ sec (90 - ⊖) = cosec ⊖]

➟ cosec 31° - cosec 31° = 0

\\

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