Math, asked by nothing5687, 6 months ago

evaluate if x-y=6 and xy=10 find x^3-y^3​

Answers

Answered by jyotirani751975
0

Answer:

Step-by-step explanation:

Cubing both sides in this equation, we have, (x-y)³ = 6³. Opening the brackets and expanding, we have, x³ - y³ - 3xy(x-y) = 216. Also, they value for xy is given as 10. So, x³ - y³ - 3(10)(6) = 216.

Answered by Anonymous
0

Refer to above image for Answer

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