Question

Evaluate inregation of tanx/secx +tanx ×dx​

Answer 1

$\frac{tan \: x}{sec \: x \:} = sin \: x$

$integrate \: \frac{tan \: x}{sec \: x} + tan \: x \: dx$

$integrate \: {sin \: x \: + tan \: x} \: dx$

integration of sin x is -cos x

integration of sin x is -cos xintegration of tan x is log |sec x|

integration of sin x is -cos xintegration of tan x is log |sec x|ANSWER: -cos x+ log |sec x| + c

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Answer 2

Answer:

secx

tanx

=sinx

integrate \: \frac{tan \: x}{sec \: x} + tan \: x \: dxintegrate

secx

tanx

+tanxdx

integrate \: {sin \: x \: + tan \: x} \: dxintegratesinx+tanxdx

integration of sin x is -cos x

integration of sin x is -cos xintegration of tan x is log |sec x|

integration of sin x is -cos xintegration of tan x is log |sec x|ANSWER: -cos x+ log |sec x| + c