Evaluate integrate (2sin x + 3cos x + 4)/(3sin x + 4cos x + 5) dx
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Let 2 sin x + 3 cos x + 4 = A(3 sin x + 4 cos x + 5) + 3(3 cos x – 4 sin x) + C Equating the co-efficients of sin x, we get 3A – 4B = 2 cos x, we get 4A + 3B = 3Read more on Sarthaks.com - https://www.sarthaks.com/536141/find-2sin-x-3cos-x-4-3sin-x-4cos-x-5-dx
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