Math, asked by arorakhushi2003, 20 days ago


Evaluate : integrate

Sin^2x/sin^2x + cos²x dx

Answers

Answered by atharvarangdale
0

sin²x + cos²x = 1

I = sin²x dx

I = 1/2 - sin2x/4

Answered by gangadharimmella
0

Answer:

sin²x+cos²x=1

1=sin²x dx

1=½-sin2x/4

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