evaluate :integration cot Square x dx
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Step-by-step explanation:
we know
cot2x-cosec2x=1
cot2x=1+cosecsquarex
after it see attachment
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Answered by
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Answer: ∫cot^2x dx = -cotx-x+c
Step-by-step explanation:
∫cot^2x dx = - cotx - x + C
Where C is any constant.
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