evaluate integration e^x(x+1)/sin^2(xe^x)
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Answer:
-Cot(xe^x)
Step-by-step explanation:
This question was asked in my recent 12th board exam recently... It was asked in a 1 mark MCQ type question
You proceed by taking x(e^x) as t and therefore dt=e^x(x+1)DX
So the integral reduces to
dt/(sint)^2 which you can write as (cosect)^2dt which is a standard integral which is equal to -cot(t)
Therefore answer is -Cot(xe^x)
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