Evaluate integration of (tanx+cotx)
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Dear student,
Please find the answer to your problem below.
I = ∫ (tanx + cotx)2 dx
I = ∫ (tan2x + cot2x + 2) dx
I = ∫ (sec2x – 1 + cosec2x – 1 + 2) dx
I = ∫sec2x dx + ∫cosec2x dx
Hence, I = tanx – cotx + c
Hope it helps.
Thanks and regards,
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mughalmantashamirza:
Tysm
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