Math, asked by mughalmantashamirza, 4 months ago

Evaluate integration of (tanx+cotx)
( \tanx +  \ cotx)^{2}

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Answered by jenan1859
2

Answer:

Dear student,

Please find the answer to your problem below.

I = ∫ (tanx + cotx)2 dx

I = ∫ (tan2x + cot2x + 2) dx

I = ∫ (sec2x – 1 + cosec2x – 1 + 2) dx

I = ∫sec2x dx + ∫cosec2x dx

Hence, I = tanx – cotx + c

Hope it helps.

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mughalmantashamirza: Tysm
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