Question

Evaluate integration of x.sinx dx

Answer 1

Answer:

- x cosx + sinx

Step-by-step explanation:

let  I = x sinx

Integration both side

I = ∫x sinx dx

I = x∫sinx dx - ∫ [ x d/dx ∫sinx dx ] dx

I = -x cosx - ∫ ( - cosx ) dx

I = -x cosx + ∫cosx dx

I = -x cosx + sinx