Question

evaluate integration sin

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Answer 1

Answer:

The integration of the form is

I=∫0πsinxdx

First we evaluate this integration by using the integral formula ∫sinxdx=–cosx, and then we use the basic rule of the definite integral ∫abf(x)dx=|F(x)|ba=[F(b)–F(a)]. So we have

∫0πsinxdx=|–cosx|π0⇒∫0πsinxdx=–|cosx|π0⇒∫0πsinxdx=–[cosπ–cos0]

Step-by-step explanation:

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