Question

evaluate integration x² dx with limit 0 to 4​

Answer 1

$\int\limits^4_0 {x^2} \, dx$

= $[\frac{x^3}{3}]$ (0 to 4)

= $(\frac{4^3}{3}) - (\frac{0^3}{3})$

= $\frac{64}{3}$

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