Question

evaluate it
3log2-1/3log27+log12-log4+3log5​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The value of given expression is 3.

Step-by-step explanation:

The given expression is

$3\log 2-\dfrac{1}{3}\log(27)+\log (12)-\log 4+3\log 5$

It can be rewritten as

$3\log 2-\dfrac{1}{3}\log(3^3)+\log (3\times 4)-\log 4+3\log 5$

Using the properties of logarithm we get

$3\log 2-\dfrac{1}{3}[3\log(3)]+\log (3\times 4)-\log 4+3\log 5$              $[\because \log a^b=b\log a]$

$3\log 2-\log(3)+\log (3)+\log (4)-\log 4+3\log 5$               $[\because \log ab=\log a+\log b]$

$3\log 2+3\log 5$

$3(\log 2+\log 5)$

$3\log (2\times 5)$

$3\log (10)$

We know that log 10 = 1.

$3(1)$

3

Therefore, the value of given expression is 3.

#Learn more

Express in terms of log 2 and log 3 log root 54^1/2 * log 243^1/3

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