Question

evaluate it by using the suitable identity (40.5)^2​

Answer 1

Answer:

$(40.5)^{2}$

$(a + b)^{2} = a^{2} + 2ab + b^{2}$

$a = 40$  

$b = 0.5$

$(40 + 0.5)^{2} = (40)^{2} + 2(40)(0.5) + (0.5)^{2}$

$= 1600 + 40 + 0.25$

$= 1640.25$

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