evaluate KP for the reaction H2 I2 = 2HI .if 2 moles each of h2 and I2 are taken initially. At equilibrium moles of HI are 2.
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Answered by
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Explanation:
: H2 + I2=== 2HI
Kc= (HI)2÷(H2)(I2)
Intial moles of H2 and I2 =2
At equilibrium ,moles of H2 and I2 = 2-x
At euilibrium moles of HI =2
From reaction x mole of H2 and I2 will give 2x mole of 2HI
Then,2x=2
X=1
Kc =(2)2÷(1)(1)
=4........
X=1
Apply in formula of Kc= (2)2
one year
hope in help
Answered by
18
guys I think this is the answer Hope it helps
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