English, asked by nandank2743, 1 year ago

evaluate KP for the reaction H2 I2 = 2HI .if 2 moles each of h2 and I2 are taken initially. At equilibrium moles of HI are 2.

Answers

Answered by love4696
33

Explanation:

: H2 + I2=== 2HI

Kc= (HI)2÷(H2)(I2)

Intial moles of H2 and I2 =2

At equilibrium ,moles of H2 and I2 = 2-x

At euilibrium moles of HI =2

From reaction x mole of H2 and I2 will give 2x mole of 2HI

Then,2x=2

          X=1

       Kc =(2)2÷(1)(1)

              =4........

  

 

          X=1

Apply in formula of Kc= (2)2

one year 

hope in help

Answered by swetha1312
18

guys I think this is the answer Hope it helps

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