Math, asked by kkg65, 1 month ago

Evaluate:lim

→0

[

1−cos 2

2

]​

Answers

Answered by prasantmandal418
0

Step-by-step explanation:

limx→01−cos2xx2=limx→01−(1−2sin2x)x2

=limx→02sin2xx2

=2(limx→0sinxx)2

=2(1)2=2

Answered by udayrehal444
1

Given, limx→0 (1 - cos 2x)(x2)

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